Un usuario de Google
The app is fine; but in the diagonalization, I can see two errors: a) If A=[1 1 0; 0 1 0; 0 0 1], the app says that 1 is the only eigenvalue (ok); but it says that only one vector corresponds to this eigenvalue (false). In fact, A is not diagonalizable. b) If A=[1 0 0; 0 2 0; 0 0 0], the app says that A is singular (ok); but it does not say any more. In fact A is diagonalizable; there are three disticnt eigenvalues. Also, the app would improve if the SVD can be computed. Good luck for this project.
Esta opinión les resultó útil a 15 personas
Artem Grinko
8 de enero de 2014
Dear, Julio Benítez , we appreciate Your comment! We will improve math core in the next update! May you help us sending Your theory on comfymobile@gmail.com
Un usuario de Google
Funciona muy bien y ademas tiene la opcion de ver el paso a paso, ademas de la resolucion de sistemas lineales por dos metodos, la recomiendo